PlaneShift

Fan Area => The Hydlaa Plaza => Topic started by: Kendaro on March 04, 2003, 06:59:11 pm

Title: New Program That Reads Minds
Post by: Kendaro on March 04, 2003, 06:59:11 pm: http://mr-31238.mr.valuehost.co.uk/assets/Flash/psychic.swf
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Post by: Raya on March 04, 2003, 07:43:24 pm: Ahahah

no matter what number you pick, the symbol you\'ll have will always be the same, no guess with that :P
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Post by: Shaded on March 04, 2003, 09:48:13 pm: it\'s pure maths
described in here...
http://www.flashmove.com/board/showthread.php?s=bd2435d9f05982a933670a883d7b2650&threadid=9479
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Post by: bbum on March 05, 2003, 04:45:31 am: i dont get it, how does it knjow what im chosing? im not giving it any imput yet it always chooses what i thought in my mind

====edit====

nm got it
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Post by: John McFo on March 11, 2003, 07:08:10 pm: Nice one...
Just look at the numbers 81, 72, 63, 54, 45, 36, 27, 18 and 9... they are always the same (each try).
Example:
99 - 18 = 81 (9+9 = 18)
98 - 17 = 81 (9+8 = 17)
97 - 16 = 81 (9+7 = 16)
and so on.
All other symbols are just for disorientation. 8)
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Post by: kaos_rich on March 11, 2003, 09:26:22 pm: thats cool try this out im giving the answer out in 48 hours so that\'ll be about 20:20 gmt on thursday

1 cow costs ?10
1 sheep costs ?1
16 hens cost ?1

you need to spend exactly ?100
you need exactly 100 animals
and you have to have at least 1 of each animal

its not hard when you thin about it but it will bug you for a while :)
p.s. you have to buy hens in 16\'s and you cant have half a sheep or cow
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Post by: kaos_rich on March 12, 2003, 08:15:41 am: cmon sum 1 have a guess you know you want to :)
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Post by: Ravenmaster on March 12, 2003, 08:31:18 am: It\'s impossible
Unless... You only said you can\'t have half a sheep or cow. so you could have 64 chickens, 6.44444444etc. cows, and 29.555555555555555etc sheep... I don\'t know. Maybe ther is a way to do it, but It\'s 2:30 in the morning, so I don\'t know.
Title: got it
Post by: Ravenmaster on March 12, 2003, 08:53:57 am: 48 hens, 47 sheep, 5 cows.
Those farm animals are pretty cheap.
I went through all my math again, more systematically and found the answer.
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Post by: Ravette on March 12, 2003, 09:22:57 am: I like the flash thing, got me for a second.
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Post by: kaos_rich on March 12, 2003, 05:14:24 pm: you got it nice one that took me a while to get when my techers told me it :)
Title: How do I found.....
Post by: joze on March 12, 2003, 06:15:43 pm: lets say X is the number of cows
Y number of sheep
Z number of packet of hens

We have:
10X + Y + Z = 100
X + Y + 16Z = 100

We know that we have to have at least one of each animal so we can say that if:
X is the number of cow -1
Y number of sheep -1
Z number of packet of hens -1
That:
10X + Y + Z = 88
X + Y + 16Z = 82

Ok. Then we know that we can\'t have more than 100 animals. Thats let us know that 1<= Z <= 6 (16*6 = 96)

lets have for 6 solution for Z.
Hypothese 1) Z=1
Then we have:
10X + Y = 87
X + Y = 66

Then 9X = 21 so X = 2.3333 That\'s impossible we can\'t have a fraction of cow.

Hypothese 2) Z=2
Then we have:
10X + Y = 86
X + Y = 50

Then 9X = 36 so X = 4 AND Y = 46
This WORKS.... X is number of cows - 1 so we need 5 cows
number of sheep => Y + 1 => 47
number of hens => (Z+1)*16 => 48

U can try with Z=3 and Z=4 etc..... no more solutions.
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Post by: Kiern on March 12, 2003, 09:38:14 pm: What the....?

Math, something else I will never understand
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Post by: Ravenmaster on March 13, 2003, 01:00:34 am: I used the equations:
C+H+S=100
10C+H/16+S=100

Since you have two equations, three unknowns, you have to choose one of those variables and assign it a value. I assigned different values for H because there are only 6 possibilities: 16, 32, 48, 64, 80, and 96. Just by plugging in each of those values and running with it, you can see there is only one answer that fits the bill.
Title: try this one!
Post by: Ravenmaster on March 13, 2003, 01:05:50 am: Given: a=b

the rest should follow. Where does it go wrong?

a=b
a^2=ab
a^2-b^2=ab-b^2 --> (a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1

:D hehehe...
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Post by: joze on March 13, 2003, 10:18:48 am: Quote
Originally posted by Ravenmaster
Given: a=b

the rest should follow. Where does it go wrong?

a=b
a^2=ab

Until here no problem

Quote
Originally posted by Ravenmaster
a^2-b^2=ab-b^2 --> (a+b)(a-b)=b(a-b)

Here U have 0 = 0 with this equation, anyone knows that u can have all u want :D.
(for exemple try with a=4)
4=4
4^2 = 4*4
4^2 - 4^2 = 4*4 - 4^2 (0=0)
..... Then with 0=0 uy can say 0*12345 = 0*54325 So
12345 = 54325 ???? No
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Post by: Ravenmaster on March 13, 2003, 06:17:42 pm: That\'s not quite it. It does have something to do with 0, but that\'s not it. 0=0 is a valid equation. You can\'t multiply one side by 12345 and the other side by 54325. There\'s another trick in there. Keep looking.
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Post by: kaos_rich on March 13, 2003, 08:47:24 pm: er yeah thats how i figured it out too i ....er love maths also im ......er just ......er going for a .....er walk yeah thats it im going for a walk (runs out the room screaming)
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Post by: Jessyn on March 13, 2003, 10:04:58 pm: ohoh, have i got a puzzle for you guys, but you may want to print it out, it took me 3 months to solve...

Dog\'s Mead puzzle (http://mywebpages.comcast.net/dharp/msc/dogsmead.html)

MWHAHAHAHHAA

Jessyn
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Post by: Kinoss on March 13, 2003, 11:38:27 pm: AAAAAAAAAAAA! MATH! my mind issss eeeexxxxpllloding!
.........................................................................................
*dead*
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Post by: Ravette on March 13, 2003, 11:39:46 pm: (http://www.imahosting.com/sigs/puzsolution.gif)

ok, there is the solution 8)
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Post by: joze on March 14, 2003, 12:07:23 pm: Quote
Originally posted by Ravenmaster
That\'s not quite it. It does have something to do with 0, but that\'s not it. 0=0 is a valid equation. You can\'t multiply one side by 12345 and the other side by 54325. There\'s another trick in there. Keep looking.

Yes 0=0 is a valid equation.
But U arrive at
(a+b)(a-b)=b(a-b)
Since a-b = 0
When U say so a+b = b it\'s no exact!

We can have 12345 * 0 = 6789*0 which is true!!!
so if a=b => 12345 (a -b) = 6789 (a-b)

but I repeat we can\'t say 12345 = 6789 because u\'ve done a division by 0!!!!
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Post by: Ravenmaster on March 18, 2003, 11:56:38 pm: Now you got it. You can\'t divide by zero. Basically, that equation simply states the infinity = 2 x infinity. Good job Joze.