PlaneShift
Fan Area => The Hydlaa Plaza => Topic started by: Xordan on April 16, 2004, 12:00:16 am
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I\'m boooored....so I decided to see if we have any clever people on this forum other than me. I\'ll start simple, and move onto harder stuff. Post when u\'ve got the answer. And yes, I know all the answers:
Logic:
The number on each gear is the number of teeth it has. If you turn any one of the gears, the others also turn.
(http://www.arcanum.co.nz/files/logic2.gif)
The gears are now in their starting position. If you start turning them and continue to turn them, eventually all three will end up at their starting positions.
How many complete turns will each gear make in order to have all three back in their starting position?
Encryption:
Heres your first piece of encryption data, you shouldn\'t find this too difficult. In fact, it\'s really easy.
\"llew enod, skool ekil uoy tog ti, retne siht edoc ot teg ruoy txen rats : munacra\"
Programming:
All you have to do is find the value of Y on the 1,000th repetition \'Y=X^3-(X+Y)\' start with Y=1, X=1 then increment X and keep recalculating Y until X reaches 1,000
Hacking/Cracking:
ok, this is a simple warm up:
43e34a8949c397215be3a22db140beec
Once one has been completed, I\'ll post up a harder one of the same type.
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The first 2 were easy, and I dun understand what you are aking in the other two? Is that a \"y\" prime of some sorts? As for the hacking, I have no bloody clue what to do with that thing...
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post the answers for the first 2, and I\'ll put harder ones up. As for the third you need to do summin like this:
set X to 1
set Y to 1
repeat this until X is greater than 1000
set Y to X^3 - (X + (the old value of Y))
increase X by 1
end of the repeated bit
print X and Y
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The wheel(gear one is easy):
The big wheel(gear) will spin 9 times, the small wheel(gear) 25 times and the medium-sized wheel(gear) 15 times.
That adds up to an all-even 225 teeth turns. ;) Next one please.
Well done, looks like you got it, enter this code to get your next star :acranum
I am not too sure about the last few words...
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lol, I\'m pulling a few of these of a challenge site I did ages ago. :) Others I make up myself. That\'s why the encryption may be a bit wierd.
Next logic:
A butcher goes to the market with $200 cash. He has to buy exactly 100 animals. There are cows, geese and chicken for sale. A cow costs $30, a goose is $2 and a chicken costs $0.50. He has to buy at least one of each animal and has to spend all his money.
How many of each animal should he buy?
Next Encryption
Wccn xiicvj, ecu\'dx avmahxn jpx rxactn
xtaveqjbct apmggxtwx, jpbr br jpx ibvrj
vxmg acnx ecu\'dx pmn jc avmah. Bj br amggxn
m rufrjbjujbct aeqpxv mtn br ctx ci jpx
ibvrj acnxr xdxv nxdxgcqxn. Pxvx br jpx txzj
acnx ecu rpcugn xtjxv : vxqqmvj
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Butcher problem:
He needs to buy 3 cows, 41 goose and 56 chicken
3+41+56=100
3*30+41*2+56*.5=200
Programming:
Threw this into excel... so I don\'t know if its right or not :P
When x=1000, y=500749501
2nd Encryption:
Good effort, you\'ve cracked the second
encryption challenge, this is the first
real code you\'ve had to crack. It is called
a substitution cypher and is one of the
first codes ever developed. Here is the next
code you should enter : reppart
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Well done. :)
Programmming 2
Give the sum of the squares of all even numbers between 0 and 2500 (inclusive).
For example 4 + 16 + 36 + ...
Logic 3
The Riddle
There are 5 houses in five different colours.
In each house lives a person with a different nationality.
These five owners drink a certain type of beverage, eat a different food and keep a certain pet.
No owners have the same pet, eat the same food or drink the same beverage.
The Clues
the Brit eats KFC
the Kiwi drinks DB Export
the Aussie lives in the Grey house
the Red house is on the immediate left of the Brown house
the person who eats Burger King rears birds
the man who eats Burger Fuel lives next to the one who drinks Stella
the man living in the center house drinks VB
the man who eats Burger Fuel lives next to the one who keeps cats
the German lives in the first house
the man who keeps horses lives next to the man who eats McDonalds
the American keeps dogs as pets
the owner who eats Wendys drinks Heineken
the Red house\'s owner drinks Lion Red
the owner of the Green house eats McDonalds
the German lives next to the Yellow house
The question
Who owns the fish? (Give Nationallity, House, Beer, and Food)
Encryption 3
mvkzgxbqwv ivaemz : bnqpazmaimk
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Cool! :)
I don\'t know about the 1st programming one, as the equation isn\'t valid with the starting data. Didn\'t try the encryption ones yet - too lazy. I\'ll make myself a proggy for the shifting first. :P
#include using namespace std; int main() { int sum=0; for(int ii=2; ii<2501; ii=ii+2){ sum+=ii^2; } cout<
1563750 is the sum. Really simple code(bah formatting).
PUPPY!!! :D I think i tried this one before... looks like the \"Einstein\" one.
For classical text riddles, that are actually PS related: http://www.planeshift3d.com/wbboard/thread.php?threadid=6918&boardid=22& :D
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Nope, wrong. ;) Try again.
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As I\'m too lazy to install/find the cds to actually do the programming.. its back to excel :P
Programming 2:
Sum of even squares between 0-2500: 22100
Edit: Just realized I may have read it wrong. Did you mean the squares go up to 2500 (which is the answer I put) or the even numbers go up to 2500? In which case the answer is huge :) = 2 607 292 500
I\'ll try the other ones when I have time to think ;)
Edit 2: Looks like I missed a digit... looks like I shouldn\'t be thinking early after I wake up :P
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2607292500, yeah.
Firstly, the ^ operator didn\'t work and secondly I declared a too small data type. And I forgot return 0; !!!:tdown:
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yup, 2607292500 is right. :)
This one is fun. :D
Programming 3
Find the products of X times Y, where X and Y are integers which are greater than 0 and less than 1000.
From these products find the sum of any which are palindromes,
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Lol, the hacking one...
use \'unescape\' much? I would type in what it translates to, but i\'m sick and feeling lazy.
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Nope never use it.
Too lazy to type in a 5 letter word!! :P
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Logic Three:
The fish is owned by the Brit in the Red House. He drinks Lion Red, and eats KFC.
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Indeed, your correct. :)
Logic 4
There are 100 switches numbered 1 to 100.
There are 100 people numbered 1 to 100.
Each person walks past and toggles all switches that are multiples of his number.
All switches are initially off.
For example person 1 toggles 1, 2, 3, ... then 2 toggles 2, 4, 6, ... then 3 toggles 3, 6, 9, ... etc. and at the end, person 100 toggles the 100th switch.
Give the product of the switches which are ON at the end?
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Logic 4:
The switches On at the end are the switches with numbers that are perfect squares (1,4,9,16,25,36,49,64,81,100).
The product of these numbers is another big number :P
13 168 189 440 000.
Encryption 3:
mvkzgxbqwv ivaemz : bnqpazmaimk
encryption answer : tfihsresaec
uh.. is the last thing supposed to be a word? :P
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Ok, for the palindromes I get 545 045 040, which is about the right order of magnitude but I haven\'t written a program to check. Am I close? I did some of the arithmetic on an RPN calculator, so I quite possibly mis-keyed something.
EDIT:
Here\'s a puzzle. Find three integers x,y,z, so that x^5 + y^5 = z^5
:D
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dfryer: Three integers you could use are: x = 1, y = -1, z = 0 (or anything where z is 0 and x and y are the same number but one of them is negative :P). Not sure if thats the answer you\'re looking for but it works :D
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logic and encryption are correct. :) Programming isn\'t. ;) I giving no hints.
Logic 5
Last logic one. :D You guys are doing good.
Give a 10 digit number which has each of the digits from 0 to 9 in it. The number is such that the first digit is divisible by 1. First 2 digits divisible by 2, first 3 by 3, first 4 by 4, so on and finally all ten digits are divisible by 10.
Encryption 4
babba aabaa baaab aabbb aaaaa ababa ababa
ababa aabaa aaaaa baaaa abbaa ababb aaaaa
abbaa babba baaba aabbb abaaa abbaa aabba
baaab. babba abbab baabb aabbb aaaaa baabb
aabaa aaabb abbab abbaa aabaa babaa aabaa
ababa. baaba aabbb aabaa aaaba abbab aaabb
aabaa babaa aabbb abaaa aaaba aabbb aabba
aaaaa abaaa abbaa baaab babba abbab baabb
babba abbab baabb baaaa abbaa aabaa babab
baaba baaab baaba aaaaa baaaa abaaa baaab
: aaaab aaaaa aaaba abbab abbaa
Yes, this is correct, no I\'m not crazy. :D
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Logic 5:
9216547830 is a number that fits what you said (if i read it right :P)
9/1 = 9;
92/2 = 46;
921/3 = 307;
9216/4 = 2304;
92165/5 = 18433;
921654/6 = 153609;
9216547/7 = 1316650;
92165478/8 = 11520685;
921654783/9 = 102406087;
9216547830/10 = 921654783
Edit: Yup, I\'m an idiot :D. When doing it in excel, I didn\'t expand the cell large enough and it automatically rounded the figures. I\'ll try it again later.
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nope wrong. Check your maths on the 9216547/7 = 1316650;
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Encryption 4:
Ye shall learn many things.
Yov have done well.
The code which gains you yovr next star is: bacon
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Excellent. :D Now for the last encryption:
Encryption 5
:P Click here (http://www.arcanum.co.nz/files/crypt.xor) :P