Author Topic: New Program That Reads Minds  (Read 4189 times)

Kendaro

  • Hydlaa Citizen
  • *
  • Posts: 303
    • View Profile

Raya

  • Traveller
  • *
  • Posts: 26
    • View Profile
(No subject)
« Reply #1 on: March 04, 2003, 07:43:24 pm »
Ahahah

no matter what number you pick, the symbol you\'ll have will always be the same, no guess with that :P

Shaded

  • Hydlaa Resident
  • *
  • Posts: 61
    • View Profile
(No subject)
« Reply #2 on: March 04, 2003, 09:48:13 pm »
don\'t argue with fools, first they pull u down to their level, then they beat u with experience.

bbum

  • Hydlaa Resident
  • *
  • Posts: 185
    • View Profile
(No subject)
« Reply #3 on: March 05, 2003, 04:45:31 am »
i dont get it, how does it knjow what im chosing? im not giving it any imput yet it always chooses what i thought in my mind

====edit====

nm got it
« Last Edit: March 05, 2003, 04:49:25 am by bbum »

John McFo

  • Wayfarer
  • *
  • Posts: 5
    • View Profile
(No subject)
« Reply #4 on: March 11, 2003, 07:08:10 pm »
Nice one...
Just look at the numbers 81, 72, 63, 54, 45, 36,  27, 18 and 9... they are always the same (each try).
Example:
99 - 18 = 81 (9+9 = 18)
98 - 17 = 81 (9+8 = 17)
97 - 16 = 81 (9+7 = 16)
and so on.
All other symbols are just for disorientation. 8)
Not being paranoid doesn\'t mean no one sneaks behind you...

kaos_rich

  • Traveller
  • *
  • Posts: 14
    • View Profile
(No subject)
« Reply #5 on: March 11, 2003, 09:26:22 pm »
thats cool try this out im giving the answer out in 48 hours so that\'ll be about 20:20 gmt on thursday


1 cow costs ?10
1 sheep costs ?1
16 hens cost ?1

you need to spend exactly ?100
you need exactly 100 animals
and you have to have at least 1 of each animal

its not hard when you thin about it but it will bug you for a while :)
p.s. you have  to buy hens in 16\'s and you cant have half a sheep or cow

always watching

kaos_rich

  • Traveller
  • *
  • Posts: 14
    • View Profile
(No subject)
« Reply #6 on: March 12, 2003, 08:15:41 am »
cmon sum 1 have a guess you know you want to  :)

always watching

Ravenmaster

  • Hydlaa Citizen
  • *
  • Posts: 364
    • View Profile
(No subject)
« Reply #7 on: March 12, 2003, 08:31:18 am »
It\'s impossible
Unless... You only said you can\'t have half a sheep or cow. so you could have 64 chickens, 6.44444444etc. cows, and 29.555555555555555etc sheep...  I don\'t know. Maybe ther is a way to do it, but It\'s 2:30 in the morning, so I don\'t know.
You are here,
You will always be here,
You will never be there.
Although you may strive to get there,
upon reaching there you will realize you are really here.
And there is everywhere else.
-Spoonjoppa

Ravenmaster

  • Hydlaa Citizen
  • *
  • Posts: 364
    • View Profile
got it
« Reply #8 on: March 12, 2003, 08:53:57 am »
48 hens, 47 sheep, 5 cows.
Those farm animals are pretty cheap.
I went through all my math again, more systematically and found the answer.  
You are here,
You will always be here,
You will never be there.
Although you may strive to get there,
upon reaching there you will realize you are really here.
And there is everywhere else.
-Spoonjoppa

Ravette

  • Hydlaa Resident
  • *
  • Posts: 67
    • View Profile
(No subject)
« Reply #9 on: March 12, 2003, 09:22:57 am »
I like the flash thing, got me for a second.


What isn\'t remembered, never happened.

Memory is merely a record...
you just need to rewrite that record.

kaos_rich

  • Traveller
  • *
  • Posts: 14
    • View Profile
(No subject)
« Reply #10 on: March 12, 2003, 05:14:24 pm »
you got it nice one that took me a while to get when my techers told me it :)

always watching

joze

  • Traveller
  • *
  • Posts: 11
    • View Profile
How do I found.....
« Reply #11 on: March 12, 2003, 06:15:43 pm »
lets say X is the number of cows
Y number of sheep
Z number of packet of hens

We have:
10X + Y + Z = 100
X + Y + 16Z = 100

We know that we have to have at least one of each animal so we can say that if:
X is the number of cow -1
Y number of sheep -1
Z number of packet of hens -1
That:
10X + Y + Z = 88
X + Y + 16Z = 82

Ok. Then we know that we can\'t have more than 100 animals. Thats let us know that 1<= Z <= 6 (16*6 = 96)

lets have for 6 solution for Z.
Hypothese 1) Z=1
Then we have:
10X + Y = 87
X + Y = 66

Then 9X = 21 so X = 2.3333 That\'s impossible we can\'t have a fraction of cow.

Hypothese 2) Z=2
Then we have:
10X + Y = 86
X + Y = 50

Then 9X = 36 so X = 4 AND Y = 46
This WORKS.... X is number of cows - 1 so we need 5 cows
number of sheep => Y + 1 => 47
number of hens => (Z+1)*16 => 48

U can try with Z=3 and Z=4  etc..... no more solutions.
« Last Edit: March 13, 2003, 10:06:22 am by joze »
-*-- Joz? --*-
 :P Be sure we will met us in PLANESHIFT
 :P

Kiern

  • Forum Addict
  • *
  • Posts: 2680
    • View Profile
(No subject)
« Reply #12 on: March 12, 2003, 09:38:14 pm »
What the....?

Math, something else I will never understand

Ravenmaster

  • Hydlaa Citizen
  • *
  • Posts: 364
    • View Profile
(No subject)
« Reply #13 on: March 13, 2003, 01:00:34 am »
I used the equations:
C+H+S=100
10C+H/16+S=100

Since you have two equations, three unknowns, you have to choose one of those variables and assign it a value. I assigned different values for H because there are only 6 possibilities: 16, 32, 48, 64, 80, and 96.  Just by plugging in each of those values and running with it, you can see there is only one answer that fits the bill.
You are here,
You will always be here,
You will never be there.
Although you may strive to get there,
upon reaching there you will realize you are really here.
And there is everywhere else.
-Spoonjoppa

Ravenmaster

  • Hydlaa Citizen
  • *
  • Posts: 364
    • View Profile
try this one!
« Reply #14 on: March 13, 2003, 01:05:50 am »
Given: a=b

the rest should follow. Where does it go wrong?

a=b
a^2=ab
a^2-b^2=ab-b^2 --> (a+b)(a-b)=b(a-b)
a+b=b
a+a=a
2a=a
2=1

 :D hehehe...
You are here,
You will always be here,
You will never be there.
Although you may strive to get there,
upon reaching there you will realize you are really here.
And there is everywhere else.
-Spoonjoppa